Sidereal time /saɪˈdɪəriəl/ is a time-keeping system astronomers use to keep track of the direction to point their telescopes to view a given star in the night sky. Briefly, a sidereal day is a "time scale that is based on the Earth's rate of rotation measured relative to the fixed stars."^[1]

From a given observation point, a star found at one location in the sky will be found at nearly the same location on another night at the same sidereal time. This is similar to how the time kept by a sundial can be used to find the location of the Sun. Just as the Sun and Moon appear to rise in the east and set in the west, so do the stars. Both solar time and sidereal time make use of the regularity of the Earth's rotation about its polar axis, solar time following the Sun while sidereal time roughly follows the stars. More exactly, sidereal time follows the vernal equinox, which is not quite fixed among the stars; Precession and nutation shift the equinox slightly from one day to the next, so sidereal time is not an exact measure of the rotation of the Earth relative to inertial space.^[2] Common time on a typical clock measures a slightly longer cycle, accounting not only for the Earth's axial rotation but also for the Earth's annual revolution around the Sun of slightly less than 1 degree per day.

A mean sidereal day is about 23 hours, 56 minutes, 4.091 seconds (23.93447 hours or 0.99726957 mean solar days), the time it takes the Earth to make one rotation relative to the vernal equinox. (Due to nutation, an actual sidereal day is not quite so constant.) The vernal equinox itself precesses slowly westward relative to the fixed stars, completing one revolution in about 26,000 years, so the misnamed sidereal day ("sidereal" is derived from the Latin sidus meaning "star") is some 0.008 seconds shorter than the Earth's period of rotation relative to the fixed stars.

The longer "true" sidereal period is called a stellar day by the International Earth Rotation and Reference Systems Service (IERS). It is also referred to as the sidereal period of rotation.

Maps of the stars in the night sky use declination and right ascension as coordinates. These correspond to latitude and longitude respectively. While declination is measured in degrees, right ascension is measured in units of time, because it was most natural to name locations in the sky in connection with the time when they crossed the meridian.

In the sky, the meridian is the imaginary north to south line that goes through the point directly overhead (the zenith). The right ascension of any object crossing the meridian is equal to the current local (apparent) sidereal time, ignoring for present purposes that part of the circumpolar region north of the north celestial pole (for an observer in the northern hemisphere) or south of the south celestial pole (for an observer in the southern hemisphere) that is crossing the meridian the other way.

Because the Earth orbits the Sun once a year, the sidereal time at any one place at midnight will be about four minutes later each night, until, after a year has passed, one additional sidereal day has elapsed compared to the number of solar days that have gone by.

Sidereal time and solar time[link]

Solar time is measured by the apparent diurnal motion of the sun, and local noon in solar time is the moment when the sun is at its highest point in the sky (exactly due south or north depending on the observer's latitude and the season). The average time for the sun to return to its highest point is 24 hours.

The Earth makes a rotation around its axis in a sidereal day; during that time it moves a short distance (about 1°) along its orbit around the sun. So after a sidereal day has passed the Earth still needs to rotate a bit more before the sun reaches its highest point. A solar day is, therefore, nearly 4 minutes longer than a sidereal day.

The stars are so far away that the Earth's movement along its orbit makes nearly no difference to their apparent direction (see, however, parallax), and so they return to their highest point in a sidereal day.

Another way to see this difference is to notice that, relative to the stars, the Sun appears to move around the Earth once per year. Therefore, there is one fewer solar day per year than there are sidereal days. This makes a sidereal day approximately 365.24⁄366.24 times the length of the 24-hour solar day, giving approximately 23 hours, 56 minutes, 4.1 seconds (86,164.1 seconds).

Precession effects[link]

The Earth's rotation is not a simple rotation around an axis that would always remain parallel to itself. The Earth's rotational axis itself rotates about a second axis, orthogonal to the Earth's orbit, taking about 25,800 years to perform a complete rotation. This phenomenon is called the precession of the equinoxes. Because of this precession, the stars appear to move around the Earth in a manner more complicated than a simple constant rotation.

For this reason, to simplify the description of Earth's orientation in astronomy and geodesy, it is conventional to chart the positions of the stars in the sky according to right ascension and declination, which are based on a frame that follows the Earth's precession, and to keep track of Earth's rotation, through sidereal time, relative to this frame as well. In this reference frame, Earth's rotation is close to constant, but the stars appear to rotate slowly with a period of about 25,800 years. It is also in this reference frame that the tropical year, the year related to the Earth's seasons, represents one orbit of the Earth around the sun. The precise definition of a sidereal day is the time taken for one rotation of the Earth in this precessing reference frame.

Definition[link]

Sidereal time, at any moment (and at a given locality defined by its geographical longitude), more precisely Local Apparent Sidereal Time (LAST), is defined as the hour angle of the vernal equinox at that locality: it has the same value as the right ascension of any celestial body that is crossing the local meridian at that same moment.

At the moment when the vernal equinox crosses the local meridian, Local Apparent Sidereal Time is 00:00. Greenwich Apparent Sidereal Time (GAST) is the hour angle of the vernal equinox at the prime meridian at Greenwich, England.

Local Sidereal Time at any locality differs from the Greenwich Sidereal Time value of the same moment, by an amount that is proportional to the longitude of the locality. When one moves eastward 15° in longitude, sidereal time is larger by one sidereal hour (note that it wraps around at 24 hours). Unlike the reckoning of local solar time in "time zones," incrementing by (usually) one hour, differences in local sidereal time are reckoned based on actual measured longitude, to the accuracy of the measurement of the longitude, not just in whole hours.

Apparent Sidereal Time (Local or at Greenwich) differs from Mean Sidereal Time (for the same locality and moment) by the Equation of the Equinoxes: This is a small difference in Right Ascension R.A. (Failed to parse (Missing texvc executable; please see math/README to configure.): dRA ) (parallel to the equator), not exceeding about +/-1.2 seconds of time, due to nutation, the complex 'nodding' motion of the Earth's polar axis of rotation. It corresponds to the current amount of the nutation in (ecliptic) longitude (Failed to parse (Missing texvc executable; please see math/README to configure.): d\psi ) and to the current obliquity (Failed to parse (Missing texvc executable; please see math/README to configure.): \epsilon ) of the ecliptic, so that Failed to parse (Missing texvc executable; please see math/README to configure.): dRA = d\psi*cos(\epsilon)

. 

Greenwich Mean Sidereal Time (GMST) and UT1 differ from each other in rate, with the second of sidereal time a little shorter than that of UT1, so that (as at 2000 January 1 noon) 1.002737909350795 second of mean sidereal time was equal to 1 second of Universal Time (UT1). The ratio varies slightly with time, reaching 1.002737909409795 after a century.^[3]

To an accuracy within 0.1 second per century, Greenwich (Mean) Sidereal Time (in hours and decimal parts of an hour) can be calculated as

GMST = 18.697374558 + 24.06570982441908 * D ,

where D is the interval, in UT1 days including any fraction of a day, since 2000 January 1, at 12h UT (interval counted positive if forwards to a later time than the 2000 reference instant), and the result is freed from any integer multiples of 24 hours to reduce it to a value in the range 0-24.^[4]

In other words, Greenwich Mean Sidereal Time exceeds mean solar time at Greenwich by a difference equal to the longitude of the fictitious mean Sun used for defining mean solar time (with longitude converted to time as usual at the rate of 1 hour for 15 degrees), plus or minus an offset of 12 hours (because mean solar time is reckoned from 0h midnight, instead of the pre-1925 astronomical tradition where 0h meant noon).

Sidereal time is used at astronomical observatories because sidereal time makes it very easy to work out which astronomical objects will be observable at a given time. Objects are located in the night sky using right ascension and declination relative to the celestial equator (analogous to longitude and latitude on Earth), and when sidereal time is equal to an object's right ascension the object will be at its highest point in the sky, or culmination, at which time it is usually best placed for observation, as atmospheric extinction is minimised.

Sidereal time is a measure of the position of the Earth in its rotation around its axis, or time measured by the apparent diurnal motion of the vernal equinox, which is very close to, but not identical to, the motion of stars. They differ by the precession of the vernal equinox in right ascension relative to the stars.
Earth's sidereal day also differs from its rotation period relative to the background stars by the amount of precession in right ascension during one day (8.4 ms).^[5] Its J2000 mean value is 23^h56^m4.090530833^s.^[6]

Exact duration and its variation[link]

A mean sidereal day is about 23 h 56 m 4.1 s in length. However, due to variations in the rotation rate of the Earth, the rate of an ideal sidereal clock deviates from any simple multiple of a civil clock. In practice, the difference is kept track of by the difference UTC–UT1, which is measured by radio telescopes and kept on file and available to the public at the IERS and at the United States Naval Observatory.

Given a tropical year of 365.242190402 days from Simon et al.^[7] this gives a sidereal day of 86,400 × Failed to parse (Missing texvc executable; please see math/README to configure.): \tfrac{365.242190402}{366.242190402} , or 86,164.09053 seconds.

Aoki et al.,^[8] defined UT1 such that the observed sidereal day at the beginning of 2000 would be ⅟1.002737909350795 times a UT1 day of 86,400 seconds, which gives 86,164.090530833 seconds of UT1. For times within a century of 1984, the ratio only alters in its 11th decimal place. This web-based sidereal time calculator uses a truncated ratio of ⅟1.00273790935.

Because this is the period of rotation in a precessing reference frame, it is not directly related to the mean rotation rate of the Earth in an inertial frame, which is given by ω=2π/T where T is the slightly longer stellar day given by Aoki et al. as 86,164.09890369732 seconds.^[6] This can be calculated by noting that ω is the magnitude of the vector sum of the rotations leading to the sidereal day and the precession of that rotation vector. In fact, the period of the Earth's rotation varies on hourly to interannual timescales by around a millisecond,^[9] together with a secular increase in length of day of about 2.3 milliseconds per century, mostly from tidal friction slowing the Earth's rotation.^[10]

Sidereal days compared to solar days on other planets[link]

Of the eight solar planets,^[11] all but Venus and Uranus have prograde rotation—that is, they rotate more than once per year in the same direction as they orbit the sun, so the sun rises in the east. Venus and Uranus, however, have retrograde rotation. For prograde rotation, the formula relating the lengths of the sidereal and solar days is

Failed to parse (Missing texvc executable; please see math/README to configure.): \text{number of sidereal days per orbital period}=1+ \text{number of solar days per orbital period}

or equivalently

Failed to parse (Missing texvc executable; please see math/README to configure.): \text{length of solar day}=\frac{\text{length of sidereal day}}{1- \tfrac{\text{length of sidereal day}}{\text{orbital period}}}.

On the other hand, the formula in the case of retrograde rotation is

Failed to parse (Missing texvc executable; please see math/README to configure.): \text{number of sidereal days per orbital period}= -1+ \text{number of solar days per orbital period}

or equivalently

Failed to parse (Missing texvc executable; please see math/README to configure.): \text{length of solar day}=\frac{\text{length of sidereal day}}{1+ \tfrac{\text{length of sidereal day}}{\text{orbital period}}}.

All the solar planets more distant from the sun than Earth are similar to Earth in that, since they experience many rotations per revolution around the sun, there is only a small difference between the length of the sidereal day and that of the solar day—the ratio of the former to the latter never being less than Earth's ratio of .997 . But the situation is quite different for Mercury and Venus. Mercury's sidereal day is about two-thirds of its orbital period, so by the prograde formula its solar day lasts for two revolutions around the sun—three times as long as its sidereal day. Venus rotates retrograde with a sidereal day lasting about 243.0 earth-days, or about 1.08 times its orbital period of 224.7 earth-days; hence by the retrograde formula its solar day is about 116.8 earth-days, and it has about 1.9 solar days per orbital period.

By convention, rotation periods of planets are given in sidereal terms unless otherwise specified.

See also[link]

• Earth rotation
• Sidereal month
• Synodic day
• Anti-sidereal time
• Nocturnal (instrument)
• Transit instrument

References[link]

• P. Kenneth Seidelmann, ed., Explanatory supplement to the Astronomical Almanac, (Mill Valley, Cal.: University Science Books, 1992)

External links[link]

Look up sidereal time in Wiktionary, the free dictionary.

• Web based Sidereal time calculator
• Build an internet synchronized sidereal clock
• For more details, see the article on sidereal time from Jason Harris' Astroinfo.

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Ted Moses, OQ (born 1950) is a Cree politician from Eastmain, a small remote village in northern Quebec, Canada. He is a former Grand Chief of the Grand Council of the Crees. In addition, Mr. Moses is a recipient of the title of "Officer" of the National Order of Quebec.

Profile[link]

Ted Moses was born in Eastmain, in the James Bay region of Quebec. After studying at Ryerson University in Toronto and McGill University in Montreal in school administration, he was Chief and Mayor of the village of Eastmain from 1987 to 1990. He was elected Grand Chief of the Crees in 1984. He is active on the international stage, speaking at numerous events about aboriginals and tolerance. Sometimes referred to as Dr. Ted Moses, he is the recipient of two honorary Doctorates of Law. [1][2]

Achievements[link]

UN recognition[link]

Chief Moses was instrumental in obtaining formal recognition for the James Bay Crees as a Non-Governmental Organization in consultative status to the United Nations. As a matter of fact, he currently serves as the Ambassador of the Council at the UN.

La Paix des Braves[link]

Another important achievement is the signing of the "Paix des Braves" (French for "Peace of the Brave"). Along with Premier Bernard Landry (of the independentist Parti Québécois, or PQ) and the government of Quebec, Moses and the Council developed this agreement. Far more than an economic deal, it was a "nation to nation" (the Cree and Quebec nations) declaration of peace after long, bitter legal disputes between Cree leaders and the Government of Quebec. The payments from the Quebec Government pays for Quebec obligations contained in the 1975 James Bay and Northern Quebec Agreement. These obligations where transferred from the Quebec Government to the Cree Government. The Cree Government decides what are the priorities.

The Paix des Braves brought big controversy but also many economic and social benefits to the Crees. The Cree communities voted in community referenda to accept the Paix des Braves. The approval was over 65% with a majority voter turnout. The Paix des Braves now in it sixth year provides 77 million dollars per year to the Cree Communities from the Quebec Government. These payments indexed by electricity, mineral, and forestry sales from the Cree traditional territory will last for another 45 years. These payments from the Quebec Government will be replaced with payments from a Cree Heritage fund set up by the Cree by investing 15% of the present payments from Quebec Government.

This was and still is widely seen as a symbolic show of mutual respect and recognition of the national status and right to self-determination of each people. It was put into concrete action when Ted Moses surprised many by supporting the re-election of Landry's Parti Québécois in the 2003 Quebec election after years of refractory attitudes of the Cree people towards Quebec sovereignism. He declared:

"I support Bernard Landry... my friend and my brother... and I will recommend to my people to support the actual Member of Parliament of Ungava, Michel Létourneau."

(Ungava is the electoral riding of the Cree of Quebec.) Moses and the PQ leader have indeed become close: Landry invited Moses to his wedding on June 26, 2004.

During the campaign for the 2004 federal election, Moses also stated that he was counting on the Bloc Québécois, the PQ's brother party in at the federal level of Canadian politics, to defend aboriginal rights at the federal level.[3][4] Moses did not formally support the BQ, saying that it "did not need it" because of its considerable lead in polls. Furthermore, he declared in a speech in Europe that Quebec and the Paix des Braves were examples to follow for the world regarding relations with aboriginal peoples.

After La Paix[link]

In 2005, Moses was defeated in his bid for Grand Chief of the Crees of Eeyou Istchee by a wide margin, taking 31.9% of the vote [5]. He was again defeated in the second round of voting, this time taking 43.3% of the vote [6].

External links[link]

• Grand Council of the Crees website